Question
If $z_{r}=\cos \frac{2 r \pi}{4}+i \sin \frac{2 r \pi}{4}$ where $r=0,1,2,3$ then $\frac{z_{0}+z_{1}}{z_{2}+z_{3}}$ equals(a) 1(b) $-1$(c) i(d) $-\mathrm{i}$
Step 1
We need to find the value of $\frac{z_{0}+z_{1}}{z_{2}+z_{3}}$. Show more…
Show all steps
Your feedback will help us improve your experience
Uma Kumari and 92 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If $z=\cos (\pi / 3)-i \sin (\pi / 3)$ then $z^{2}-z+1=$ (a) $-2 \mathrm{i}$ (b) 2 (c) 0 (d) $-2$
If $Z=\cos (4 \pi / 7)+i \sin (4 \pi / 7)$ then $\operatorname{Re}\left(z+z^{2}+z^{3}\right)=$ (a) $\cos (\pi / 3)$ (b) $\cos (2 \pi / 3)$ (c) $\cos (\pi / 6)$ (d) $\cos (5 \pi / 6)$
Find $z_{1} z_{2}$ and $\frac{z_{1}}{z_{2}}$. $$z_{1}=3\left(\cos \frac{3 \pi}{4}+i \sin \frac{3 \pi}{4}\right), z_{2}=\frac{2}{3}\left(\cos \frac{4 \pi}{3}+i \sin \frac{4 \pi}{3}\right)$$
Complex Numbers
The complex plane
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD