Question
If $z=r(\cos \theta+i \sin \theta)$ is a complex number then $z^{n}=\left[\cos \left(\frac{1}{-}\right)+i \sin \left(-\frac{1}{n}\right)\right]$
Step 1
It is in the polar form, $z=r(\cos \theta+i \sin \theta)$, where $r$ is the magnitude and $\theta$ is the argument or angle. Show more…
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