Question
If $z=x+i y$, determine the Cartesian equation of the locus of the point $z$ which moves in the Argand diagram so that$$|z+j 2|^{2}+|z-j 2|^{2}=40$$
Step 1
We can rewrite $z+j2$ and $z-j2$ as $x+i(y+2)$ and $x+i(y-2)$ respectively. Show more…
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If $z=x+i y$, determine the Cartesian equation of the locus of the point $z$ which moves in the Argand diagram so that $$ \left.|z+| 2\right|^{2}+\left.|z-| 2\right|^{2}=40 $$
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Further problems
Determine the locus defined by $|z|=4$, given that $z=x+j y$ If $z=x+j y$, then on an Argand diagram as shown in Figure $23.3$, the modulus $z$, $$ |z|=\sqrt{x^{2}+y^{2}} $$ Figure 23.3 In this case, $\sqrt{x^{2}+y^{2}}=4$ from which, $x^{2}+y^{2}=4^{2}$ From Chapter $14, x^{2}+y^{2}=4^{2}$ is a circle, with centre at the origin and with radius 4 The locus (or path) of $|z|=4$ is shown in Fig. 23.4.
If $z=x+j y$, determine the equations of the loci in the Argand diagram, defined by: (a) $\left|\frac{z+2}{z-1}\right|=2$ and (b) $\arg \left\{\frac{z-1}{z+2}\right\}=\frac{\pi}{2}$
Further problems F.2
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