00:01
Part a, we know that both gases are noble.
00:08
Therefore, we know that the change in entropy of nitrogen gas plus the change in entropy of argon gas would be equal to nrln v2 divided by v1, and this is equaling nrln of 2.
00:24
And this is equaling nrln of 2.
00:27
Now, we can say that because both gases are noble, each gas expands without change in temperature.
00:46
And if that's the case, we can say that the total entropy would be equal to change in entropy of n2 plus change in entropy of ar.
01:02
R and this would be equal to essentially this times two.
01:12
So two times nr, ln of 2.
01:15
And at this point, we can actually solve.
01:17
So the total change in entropy would be equal to two times one mole.
01:24
This would be 8 .3, 14 joules per mole per kelvin, and then times ln of 2, giving us 11 .5 joules per kelvin.
01:37
So this would be our answer for part a...