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(II) A 1200 -kg car rolling on a horizontal surface has speed $v=65 \mathrm{km} / \mathrm{h}$ when it strikes a horizontal coiled spring and is brought to rest in a distance of $2.2 \mathrm{m} .$ What is the spring stiffness constant of the spring?
Step 1
We can do this by multiplying the given speed by the conversion factor $\frac{1000 \, \text{m}}{3600 \, \text{s}}$. This gives us: \[v = 65 \, \text{km/h} \times \frac{1000 \, \text{m}}{3600 \, \text{s}} = \frac{325}{18} \, \text{m/s}\] Show more…
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(II) A $1200 - \mathrm { kg }$ car rolling on a horizontal surface has speed $v = 66 \mathrm { km } / \mathrm { h }$ when it strikes a horizontal coiled spring and is brought to rest in a distance of 2.2$\mathrm { m }$ . What is the spring constant of the spring?
A $1200-\mathrm{kg}$ car rolling on a horizontal surface has speed $v=66 \mathrm{~km} / \mathrm{h}$ when it strikes a horizontal coiled spring and is brought to rest in a distance of $2.2 \mathrm{~m}$. What is the spring constant of the spring?
(II) A 1200-kg car moving on a horizontal surface has speed $v =$ 85 km/h when it strikes a horizontal coiled spring and is brought to rest in a distance of 2.2 m. What is the spring stiffness constant of the spring?
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Mechanical Energy and Its Conservation
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