(II) A 1.5-m length of wire carrying 4.5 A of current is oriented horizontally. At that point on

Name: Problem 4, Chapter 20: Physics Principles with Applications
Uploaded: 2020-07-24T13:22:41-08:00
Duration: 1 min 29 s
Channel: Yaqub Khan
Description: (II) A 1.5-m length of wire carrying 4.5 A of current is oriented horizontally. At that point on the Earth's surface, the dip angle of the Earth's magnetic field makes an angle of 38^∘ to the wire. Estimate the magnitude of the magnetic force on the wire due to the Earth's magnetic field of 5.5 ×10^-5 T at this point.

step 1 magnitude of magnetic force on straight wire is equal to current times length of straight wire t

Question

(II) A $1.5-\mathrm{m}$ length of wire carrying 4.5 $\mathrm{A}$ of current is oriented horizontally. At that point on the Earth's surface, the dip angle of the Earth's magnetic field makes an angle of $38^{\circ}$ to the wire. Estimate the magnitude of the magnetic force on the wire due to the Earth's magnetic field of $5.5 \times 10^{-5} \mathrm{T}$ at this point.

   (II) A $1.5-\mathrm{m}$ length of wire carrying 4.5 $\mathrm{A}$ of current is oriented horizontally. At that point on the Earth's surface, the dip angle of the Earth's magnetic field makes an angle of $38^{\circ}$ to the wire. Estimate the magnitude of the magnetic force on the wire due to the Earth's magnetic field of $5.5 \times 10^{-5} \mathrm{T}$ at this point.

Physics Principles with Applications

Douglas C. Giancoli 6th Edition

Chapter 20, Problem 4

Instant Answer

Solved by Expert Yaqub Khan

07/24/2020

Step 1

Step 1: The magnetic force on a current-carrying wire is given by the formula: \[ F = I \cdot L \cdot B \cdot \sin(\theta) \] where: - $F$ is the magnetic force, - $I$ is the current, - $L$ is the length of the wire, - $B$ is the magnetic field strength, Show more…

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(II) A $1.5-\mathrm{m}$ length of wire carrying 4.5 $\mathrm{A}$ of current is oriented horizontally. At that point on the Earth's surface, the dip angle of the Earth's magnetic field makes an angle of $38^{\circ}$ to the wire. Estimate the magnitude of the magnetic force on the wire due to the Earth's magnetic field of $5.5 \times 10^{-5} \mathrm{T}$ at this point.

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Key Concepts

Magnetic Dip Angle

The magnetic dip angle refers to the angle between the Earth's magnetic field and the horizontal plane. It is an important parameter in geomagnetism as it affects how the magnetic field interacts with horizontal conductors or other structures. The dip angle must be considered when computing the component of the Earth's magnetic field that contributes to forces on current-carrying conductors.

Magnetic Force on a Current-Carrying Conductor

This concept involves the force exerted on a conductor carrying an electric current when it is placed in a magnetic field. The force is calculated using the formula F = I · L · B · sin(?), where I is the current, L is the length of the conductor, B is the magnetic field strength, and ? is the angle between the direction of the current and the magnetic field. This principle is key in understanding how electric currents interact with magnetic fields to produce mechanical forces.

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