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(II) A $180-\mathrm{km} / \mathrm{h}$ wind blowing over the flat roof of a housecauses the roof to lift off the house. If the house is6.2 $\mathrm{m} \times 12.4 \mathrm{m}$ in size, estimate the weight of the roof.Assume the roof is not nailed down.

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$1.2 \times 10^{5} N$

Physics 101 Mechanics

Chapter 13

Fluids

Fluid Mechanics

University of Washington

Hope College

University of Sheffield

University of Winnipeg

Lectures

03:45

In physics, a fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases, plasmas and, to some extent, plastic solids.

09:49

A fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases and plasmas. Fluids display properties such as flow, pressure, and tension, which can be described with a fluid model. For example, liquids form a surface which exerts a force on other objects in contact with it, and is the basis for the forces of capillarity and cohesion. Fluids are a continuum (or "continuous" in some sense) which means that they cannot be strictly separated into separate pieces. However, there are theoretical limits to the divisibility of fluids. Fluids are in contrast to solids, which are able to sustain a shear stress with no tendency to continue deforming.

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A 180-km$/$h wind blowing …

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Roof of house in wind The …

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The mass of the roof of a …

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(II) If wind blows at 35 $…

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The construction of a flat…

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A hurricane wind blows acr…

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Presents one method for mo…

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In a tornado or hurricane,…

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A house has a roof with th…

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Interactive Solution $\und…

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The wind blows with a spee…

So here we're going to assume that there's no appreciable appreciable height difference between the two sides of the roof. And then we're just going to apply Bernoulli's equation and we can say pee inside plus 1/2 roe v in sides squared plus row G Y inside will be equaling the pressure outside out plus 1/2 Roe v Out squared plus row G. Why out? And we're going to then say that the difference in pressure pressure inside, minus the pressure outside would be equal in 1/2 times the density of air multiplied by the velocity outside squared, uh, actually out squared. Given that the velocity inside, it's negligible, this would be equaling the force of the air divided by the cross sectional area where the surface area rather of the group And so we can say that then the force of the air would be equaling 1/2 times the density of the air times the velocity of the air outside squared times, the surface area of the roof. And so we say that the force of the air would be equaling 1/2 times 1.29 kilograms per cubic meter multiplied by it would be 180 kilometers per hour for every one meter per second. There are 3.6 kilometers per hour and this quantity would be squared. This would be multiplied by 6.2 meters, times 12.4 meters and so the force of the air would be equaling approximately 1.2 times 10. Either. That's I got 1.2 times 10 to the fifth Newton's. This would be our final answer. That is the end with the solution. Thank you for

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