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(II) A 6.620 -kg wood block is firmly attached to a very lighthorizontal spring $(k=180 \mathrm{N} / \mathrm{m})$ as shown in Fig. $35 .$ Thisblock-spring system, when compressed 5.0 $\mathrm{cm}$ and released,stretches out 2.3 $\mathrm{cm}$ beyond the equilibrium position before stopping and turning back. What is the coefficient of kinetic friction between the block and the table?

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Physics 101 Mechanics

Chapter 8

Conservation of Energy

Work

Kinetic Energy

Potential Energy

Energy Conservation

Moment, Impulse, and Collisions

Cornell University

University of Michigan - Ann Arbor

Simon Fraser University

University of Winnipeg

Lectures

04:05

In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

04:30

In classical mechanics, impulse is the integral of a force, F, over the time interval, t, for which it acts. In the case of a constant force, the resulting change in momentum is equal to the force itself, and the impulse is the change in momentum divided by the time during which the force acts. Impulse applied to an object produces an equivalent force to that of the object's mass multiplied by its velocity. In an inertial reference frame, an object that has no net force on it will continue at a constant velocity forever. In classical mechanics, the change in an object's motion, due to a force applied, is called its acceleration. The SI unit of measure for impulse is the newton second.

04:10

(II) A 0.620 -kg wood bloc…

07:54

(III) A 0.620 -kg wood blo…

0:00

A 450g wood block is firm…

02:44

A 0.620 kg wood block is f…

02:23

You push a 3.9 kg block ag…

04:43

(II) A 180 -g wood block i…

06:04

A block with mass 0.50 $\m…

03:34

A block with mass 0.50 kg …

02:02

Block Against Horizontal S…

02:15

You push a $2.0 \mathrm{~k…

02:53

A block with mass $0.50 \…

02:00

You push a 2.0 $\mathrm{kg…

(III) A 280 -g wood block …

08:51

$\bullet$ $\bullet$ A bloc…

05:42

When a 3.0-kg block is pus…

so it says a 6.62 kilogram per block is firmly attached to every light horizontal spring. So in this case, we enjoy figure of the situation first. So there is a block and the mass off this a 6.62 kilograms. The force constant of the spring is given as 1 80 needless sperm eater and the block is compressed. So what happens is that first of all, the block is compressed. So this is its initial position and is compressed this 00 and it is compressed too. 35 Sorry, compressed your five centimeters. So this is five centimeters and then released. So what is saying is that when there's a friction in the scenario and this is the Korean position So the block executes simple harmonic motion, and what happens is that well, the thing is that it stretches 2.3 centimeters. We are in the Ecuadorian position before stopping and turning back. So that is our question. So in this case again, we'll use the conservation of energy bid the non conservative for us acting on it, and we know that the force off friction is equals to UK mg all right now, the location one represents the block at the compressed locations. So this is our location One okay. And the location to represents the block at the max. It's Mom stressed Position So which means this is a location too. And this is they could be in position, which is at zero common zero. So our dislocation we have V one is equals to zero and the x one, the displacement is negative point or five meters because it is toward the left or far is your level and a dislocation. The block comes to rest. So Vito's equals to zero and x two is equals 2.23 meters. So let's apply the conservation of energy. So we have the total energy even should be equals the total energy and be too. But this is not the case in this scenario, because the restriction so the energy at one should be equal to the energy. A to bless some work done by the friction force. So energy at one is equals to half and V one squared less have okay x one squared and energy to Z equals to half and Vito squad less half gay extra squared. Bless the force of friction. And this is the displacement so that no displacement is extra minus explain. So now we just plug it in the values in this equation. So as you can see that even a zero So therefore be a zero less half gay X one squared. Bless. So in fact, it is just simply zero plus half key X one squared, a little insider, something else. On the right hand side, we have the velocity, Richard zero again at this point. So this is zero less half. Okay. Excuse squad. Less mu k and G s we have seen is the force of friction Times x two minus x one. So we'll solve that on the next page. So writing this here we get the equation. All right again. Half gay X one squared is equals 2/2 gay extra squared. Bless me. Okay, MG x two minus 61 So now we need to find the value of Mucha simple by rearranging the terms you get. Mu K is equals two. Okay, x one squared minus extra squad divided by two times M jean x two minus X one. All right. So in this equation if you just plug it in the values according to the equation. But this could be actually we simplified. We can accelerate on the numerator as X negative extra squared minus X one squared. I've just multiplied the whole thing by negative and divided by two mg x two minus x one. Now we know that he s squared minus B squared is equals two a minus B x two minus excellent and a plus B x to place x one divided by two mg x two minus X one was actually cancels and be a left over with equation. So therefore we know plug in the values negative 1 80 times negative 0.5 Class point or 23 which is extra plus x one divided by two times the mass ridges 0.62 times 9.8 If he saw that, you will get a point for as the coefficient of friction

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