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(II) (a) A grinding wheel $0.35 \mathrm{~m}$ in diameter rotates at $2500\space \mathrm{rpm}$. Calculate its angular velocity in $\mathrm{rad/s}$. (b) What are the linear speed and acceleration of a point on the edge of the grinding wheel?

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(a) 262 $\mathrm{rad} / \mathrm{s}$(b) 46 $\mathrm{m} / \mathrm{s}$$1.2 \times 10^{4} \mathrm{m} / \mathrm{s}^{2}$

Physics 101 Mechanics

Chapter 10

Rotational Motion

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

Cornell University

University of Michigan - Ann Arbor

Simon Fraser University

University of Winnipeg

Lectures

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

02:49

(II) (a) A grinding wheel …

01:46

(II) $(a)$ A grinding whee…

03:36

01:27

(a) A grinding wheel $0.35…

02:23

(a) A grinding wheel 0.35m…

02:06

A gyroscope flywheel of ra…

03:31

(II) A 61-cm-diameter whee…

02:05

(II) A 70 -cm-diameter whe…

03:44

01:31

A point on the rim of a $0…

03:48

(II) $\mathrm{A} 64$ -cm-d…

00:54

A point on the rim of a 0.…

02:44

01:11

A wheel of radius $0.20 \m…

03:41

Gyroscope A gyroscope flyw…

So for part A, we can find the angular velocity in terms of radiance per second, this would be 2500 revolutions per minute. There are two pi radiance for everyone revolution. And then for every one minute there are 60 seconds and we're getting that The angular velocity is gonna be equaling 260 to approximately radiance for a second. We can then say, for part B, the linear velocity would be equaling the angular velocity times the radius are and so this would be equal to 261.8 will round at the very end Radiance per second multiplied by 0.175 meters. This is equaling approximately 46 meters per second. This would be here Ah, one answer for part B and then to find the radial acceleration, this would simply be equaling Omega squared are and so this would be 261.8 radiance per second Quantity squared multiplied by 0.175 meters and we find that the radio acceleration is equally approximately 1.2 times 10 to the fourth meters per second squared. This would be your final answer for Part B and our final answer for party. That is the end of the solution. Thank you for watching.

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