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Question number 11 asks us, what is the speed of an astronaut in a rotational device that exerts 7 .85 times her weight on her back? to get an idea of what's happening here, let's draw our astronaut in the seat of the rotational device here.
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Here it is.
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There's the arm of the device right there.
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And in the back of her is where a force is applied.
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And she's traveling forward at some velocity.
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And there's the central shaft right there.
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Now, the length of the arm attached to the central shaft and the astronaut's chair is what we're going to call r.
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And force is applied to the back of her at a magnitude of 7 .85 times her weight.
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And this force is rotational.
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Now, since she's being spun in a horizontal circle, the force she would feel would be equal to her centripetal acceleration.
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So, f sub r is going to be equal to m times v squared over r.
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We also know that f sub r is equal to 7 .85w, 7 .85 times the astronaut's weight.
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Her weight can be thought of as the product of her mass and the gravitational constant.
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So we can rewrite this as 7 .85 mg.
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Now we can set 7 .85 times mg equal to m times v squared over r.
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We don't know what the mass of our astronaut is, but we don't need to, because both the ms cancel out on...