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(II) A fire hose held near the ground shoots water at a speed of 6.5 $\mathrm{m} / \mathrm{s}$ . At what angle(s) should the nozzle point in order that the water land 2.5 $\mathrm{m}$ away (Fig. 40$) ?$Why are there two different angles? Sketch the two trajectories.

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$\theta=18^{\circ}$ and $72^{\circ}$

Physics 101 Mechanics

Chapter 3

Kinematics in Two or Three Dimensions; Vectors

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

University of Washington

Simon Fraser University

Hope College

University of Sheffield

Lectures

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

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A fire hose held near the …

04:15

(II) A fire hose held near…

02:02

06:09

The fireman wishes to dire…

06:27

A firefighting crew uses a…

02:25

15:13

04:45

01:55

A fire hose ejects a strea…

03:19

SSM A fire hose ejects a s…

08:05

A water sprinkler is set t…

So here we need Thio. Apply the range formula from example 3 10 so the range formula would be equal to be initial squared times Sign of to data initial So the initial angle measure divided by the acceleration due to gravity G and again, this is only going to be applied when the change in the displacement in the UAE direction equal zero meters. So if it's not, if the change in displacement in the UAE direction equals does not equal zero meters rather you cannot use this equation. However, here it does equal zero meters. Therefore we can use this equation and we're going to actually solve for theta initial. So we can say sign of two fada initial would be equal to RG divided by the initial velocity squared. And so we can say that this is going to be equal to 2.5 meters multiplied by 9.8 meters per second squared divided by this would be 6.5 meters per second quantity squared. This is equaling 0.5799 So we can say that state a initial, uh, leave the tooth data initial rather equals art sign of 0.5799 and this is going to be equal to Rather, we can say that if we were to solve this divide by two, we can actually get ah, the two angle measures of 18 degrees and 72 degrees. Now this is there. These are the two angles. There are two angles because each angle gives the same range. If one angle is theta equals 45 degrees, plus some angle measure, the other answer would be 45 degrees, minus that same angle measure. So this essentially would be, uh these two angle measures would give the same exact range, so these would be the two answers. And then the question asks you to actually sketch the two trajectories, and these would be the sketch of the two direct trajectories. This would represent the 18 degree trajectory, and then this path is the 72 degree trajectory. That is the end of the solution. Thank you for watching

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