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(II) A fish tank has dimensions 36 $\mathrm{cm}$ wide by 1.0 $\mathrm{m}$ long by0.60 $\mathrm{m}$ high. If the filter should process all the water in thetank once every $4.0 \mathrm{h},$ what should the flow speed be in the3.0 -cm-diameter input tube for the filter?

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$v=0.0212 \mathrm{~m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 13

Fluids

Fluid Mechanics

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

Simon Fraser University

University of Winnipeg

Lectures

03:45

In physics, a fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases, plasmas and, to some extent, plastic solids.

09:49

A fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases and plasmas. Fluids display properties such as flow, pressure, and tension, which can be described with a fluid model. For example, liquids form a surface which exerts a force on other objects in contact with it, and is the basis for the forces of capillarity and cohesion. Fluids are a continuum (or "continuous" in some sense) which means that they cannot be strictly separated into separate pieces. However, there are theoretical limits to the divisibility of fluids. Fluids are in contrast to solids, which are able to sustain a shear stress with no tendency to continue deforming.

02:02

A fish tank has dimensions…

0:00

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Water flows through a 2.5 …

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Water flows through a $4.0…

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Water flows through a pipe…

04:22

A 4.0 -mm-diameter hole is…

02:07

Oil flows through a pipe $…

03:12

Water flows at $1.20 \time…

02:41

A 1.0 -cm-diameter pipe wi…

Water is leaking out of an…

01:38

(II) $\mathrm{A} \frac{5}{…

01:03

A large cylindrical tank i…

So we want to find the velocity of the water coming out of the tube so we can say that the volumetric floor it by definition would be equal to a and rather a total amount of volume divided by a change in time. This is gonna be equal to the cross sectional area of the tube times the velocity of the water going through that tube so we can solve for V and say the velocity is going to be equal to the In this case, it would be the this it would be the volume divided by, uh, the area times the change in time. And to find volume, we can simply substitute for the length times, the with times the height on again, divided by the cross sectional area of the tube. So pi r squared and then times again, delta T. At this point, we can solve and say that this is gonna be equal to, um again the length 0.36 meters times the with of one meter times the height of 0.60 meters and this is divided by pi times 0.15 meters. Quantity squared times The change in t of four hours times 3600 seconds per hour and we find that the velocity is gonna be equal 2.0 212 meters per second. So this will be our final answer. That is the end of the solution. Thank you for watching.

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