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(II) A grasshopper hops down a level road. On each hop,the grasshoper launches itself at angle $\theta_{0}=45^{\circ}$ andachieves a range $R=1.0 \mathrm{m}$ . What is the average hori-zontal speed of the grasshopper as it progresses down theroad? Assume that the time spent on the ground betweenhops is negligible.

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2.2 $\mathrm{m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 3

Kinematics in Two or Three Dimensions; Vectors

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

Cornell University

Rutgers, The State University of New Jersey

Hope College

Lectures

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

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the question ass. A nurse says. A grass hopper hops down a level road on he chopped the grass Hopper lodges itself in an angle theta not is equal to 45 degrees and achieves arrange our equals one meter. What is the average horizontal speed of the grass hopper as it progresses down the road, assume that the time spent on the ground between hops is negligible. Okay, so I went ahead and wrote down what we were given here and that is that the initial angle they did not is 45 degrees that the hasn't grasshoppers jumping it jumps arrange. Our azi called a 1.0 meters were on earth. So we know that gravity, which is going to play a part here, is 9.8 meters per square second. And the question is how Aah! What is the velocity of the grass hopper in the horizontal direction in the extraction? In order to do that, we need to first find the velocity of the grass hopper period when it jobs. So we just call that the zero First, we need to find that what is that equal? In order to do that, we're going to take into account the range formula. Grange is equal to V not right. Which is what we're going to try to find. Ah, excuse me. Table of Venus squared Time's sign two times the angle. Redraw that. Which is saying or not? Okay. Divided by gravity G and we want to solve for V not V not. It's squared. So in order to get it by itself in a square root. Okay, our gets multiplied by the G. No. Okay. And this is divided by side to favor. Okay, so if you plug in all the values that we have here we have this is equal to the square root of are, which is one meter times gravity 9.8 meters per second squared, divided by signed to theta. Okay, so signed to Fada Fada is 45 is the sign of 90 degrees. So right, so if you plug all of this in your calculator and figure out what this is, it comes out Tio equal 3.13 meters per second. Okay, but that is just the velocity. We want the horizontal component of velocity or the X component of velocity. Piece of X is equal to the velocity Times Co Sign of the angle. Grillet two decks co sign because we're dealing with X here, the angle's 45. So Time's a co sign of 45. Right Veena is 3.13 So 3.13 times the coastline of 45. You plug that into your calculator and comes out to be 2.2 commuters her second.

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