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(II) $( a )$ How much work is done by the horizontal force $F _ { \mathrm { P } } = 150 \mathrm { N }$ on the 18$\mathrm { kg }$ block of Fig. 29 when the force pushes the block 5.0$\mathrm { m }$ up along the $32 ^ { \circ }$ frictionless incline? (b) How much work is done by the gravitational force on the block during this displacement? (c) How much work is done by the normal force? (d) What is the speed of the block (assume that it is zero initially) after this displacement? [Hint. Work-energy involves network done.

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$$=4.3 \mathrm{m} / \mathrm{s}$$

Physics 101 Mechanics

Chapter 7

Work and Energy

Work

Kinetic Energy

Potential Energy

Energy Conservation

Cornell University

University of Washington

University of Winnipeg

Lectures

04:05

In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

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In physics, the kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. The kinetic energy of a rotating object is the sum of the kinetic energies of the object's parts.

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7.63. So we have this horizontal force here pushing a block up a frictionless incline. So we want to find out how much work this force does, how much work gravity does, how much work the normal force does. And then, with the final speed of the block, will be assuming that it starts from rest. So for party here, the, um, angle between the direction of the force and the displacement of this block is 32 degrees use. So the work done by this force is going to be its magnitude times the distance of five meters times the coastline of 32 degrees. So this is 640 Jules. Now for the work that gravity is doing the force. The magnitude of the forest is, of course, just the weight of the block still moving the same distance. And now the the angle between the force of gravity and the displacement is 122 degrees. So the work the gravity does is negative. 470. Jules. Now the normal force he's here is perpendicular to the displacement. And so the normal force the zero work now to find the speed. We can use the relationship between work and kinetic energy, so it needs to be the total work. So did the work done by the force, plus the worked up by gravity plus the worked up by the normal forest, which is zero is going to eat with the final kinetic energy of our block. So final speed is the square root of two times the network divided by the Mass. This is 640 minus 470 Jules, and so its final speed is 4.3 meters per second.

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