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(II) A hydraulic press for compacting powdered samples has alarge cylinder which is 10.0 $\mathrm{cm}$ in diameter, and a smallcylinder with a diameter of 2.0 $\mathrm{cm}$ (Fig. $51 ) .$ A lever is attachedto the small cylinder as shown. The sample, which is placed onthe large cylinder, has an area of 4.0 $\mathrm{cm}^{2} .$ What is the pressureon the sample if 350 $\mathrm{N}$ is applied to 0 the lever?

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$4.4 \times 10^{7} \mathrm{N} / \mathrm{m} / \mathrm{m}$

03:50

Averell Hause

Physics 101 Mechanics

Chapter 13

Fluids

Fluid Mechanics

Rutgers, The State University of New Jersey

University of Washington

Hope College

University of Winnipeg

Lectures

03:45

In physics, a fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases, plasmas and, to some extent, plastic solids.

09:49

A fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases and plasmas. Fluids display properties such as flow, pressure, and tension, which can be described with a fluid model. For example, liquids form a surface which exerts a force on other objects in contact with it, and is the basis for the forces of capillarity and cohesion. Fluids are a continuum (or "continuous" in some sense) which means that they cannot be strictly separated into separate pieces. However, there are theoretical limits to the divisibility of fluids. Fluids are in contrast to solids, which are able to sustain a shear stress with no tendency to continue deforming.

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(II) A hydraulic press for…

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A $\textbf{hydraulic press…

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The hydraulic system of a …

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The diameter of the large …

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Two hydraulic piston/cylin…

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The pistons of a hydraulic…

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The output piston of a hyd…

03:21

A hydraulic lift in a serv…

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The hydraulic press shown …

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The small circular piston …

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A pneumatic cylinder (a pi…

session. All right. We've got a hydraulic press with a large cylinder and a small cylinder. So I'm gonna draw it like this large cylinder and then small cylinder diameter here 10 centimeters. But I'm going to convert that into meters and the diameter here, meet. Okay, the sample. This sample that's on the large cylinder has an area of four. We're centimeters. So, if you press here with a force of 300 50 Newton was the pressure on the samp. Well, the force here, which I'll say force so be for big is going to be the original force time's D over D. Weird. So, and then I'm going to take that force and I'm going to divide it among the four centimeters square. So the pressure is going to be F subi over a which is going to be F. D. Over D. Squared over a. So let me put that into a calculator, dragging the calculator over F. Was 350 D. Is 0.1 over a 0.2 squared over four. So that would be newton's per square centimeters, but there are 100 centimeters in a meter. Right? That gives me 2.2 times 10 to the seventh power. Newtons per square meter. Now I don't see the picture. Um but I'm suspecting that in the picture there's a lever because I can't get to the book and the arm on the lever is probably twice as long as the pivot. All right. And then we put the force here, if it was twice as long to the pivot, then we could multiply our force to be not just 350 but 350 times two, which would be 700 newtons. Um That would give us the uh 4.4 times 10 to the seventh. Newtons per square metre uh indicated as the answer. So unfortunately I don't have a copy of the book, so I don't know if this lever is here, but if it is and I suspect that it is then um the force would actually be double the force here, which would be the 700 newtons and then multiplied by the ratio of the diameters, which is really the ratio of the areas reaches diameter squared, um divide that by the area of the sample. And that gives us the answer, Thank you for watching.

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