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(II) A lever such as that shown in Fig. 20 can be used to lift objects we might not otherwise be able to lift. Show that the ratio of output force, $F _ { \mathrm { O } } ,$ to input force, $F _ { \mathrm { I } } ,$ is and $\ell _ { \mathrm { O } }$ from the pivot by $F _ { \mathrm { O } } / F _ { \mathrm { I } } = \ell _ { 1 } / \ell _ { \mathrm { O } }$ . Ignore friction and the mass of the lever, and assume the work output equals work input.

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$$\frac{F_{\mathrm{O}}}{F_{\mathrm{I}}}=\frac{l_{1}}{l_{\mathrm{O}}}$$

Physics 101 Mechanics

Chapter 7

Work and Energy

Work

Kinetic Energy

Potential Energy

Energy Conservation

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Lectures

04:05

In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

03:47

In physics, the kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. The kinetic energy of a rotating object is the sum of the kinetic energies of the object's parts.

02:47

(II) A lever such as that …

02:26

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02:16

01:37

01:30

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02:15

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03:23

Here's a diagram of what's happening. We want to prove that the force of the output force divided by the force of the input force is equal to Elsa. I developed Elsa Bow so we can say that the work of the output equals the work of the input which would equal that I'll put age output equals f input h and put, um, And if we were to divide, we can say that the force of the output about by the force of the input equals h. So I divided by H. O. However, in the diagram, we see that h I remember h ovo equals how's alli over also. So you can see that in the diagram. This is simply due to geometry. So in this case, or we can say similar triangles. So in this case, we can say that the force of the output Ah, where the output forced about about the input force is going to be equal to again. Elsa by I else? No. So this would be our final answer. Well, that would be us proving, Stan, that this relationship exists. That is the end of the solution. Thank you for watching

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