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(II) A passenger on a boat moving at 1.70 $\mathrm{m} / \mathrm{s}$ on a still lakewalks up a flight of stairs at a spced of 0.60 $\mathrm{m} / \mathrm{s}$ . Fig. $51 .$ Thestairs are angled at $45^{\circ}$ pointing in the dircction of motionas shown. Write the vector velocity of the passenger relativeto the water.

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$(2.12 \hat{\mathbf{i}}+0.42 \hat{\mathbf{j}}) \mathrm{m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 3

Kinematics in Two or Three Dimensions; Vectors

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

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Lectures

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

04:22

(II) A passenger on a boat…

01:31

passenger on boat moving a…

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A passenger on a boat movi…

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(II) A boat, whose speed i…

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$\because$ A passenger wal…

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Velocity of a Boat $A$ boa…

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07:11

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04:33

Our question says that a passenger on a boat moving at 1.7 meters per second on a still lake walks up a flight of stairs at a speed of 0.6 meters per second. Say you're 51. The stairs are in an angle of 54 degrees, pointing in the direction of motion has shown right the vector velocity of the passenger relative to the water. So I wrote out here what we were given. I wrote that the velocity of the boat, which I write his visa be his 1.7 meters per second and I write that is in the eye had direction. So I say the boat is travelling in the ex direction or I had direction. Then the velocity of the person or the passenger, which are as Visa P, is equal to 0.6 meters per second. But it's at an angle because he's walking up the stairs that's going to be multiplied by the coastline of the angle. In the I had direction right for X and plus the sine of the angle in the jihad direction for why, okay and the angle were also given us 45 degrees and I draw a little diagram here of the velocity of the boat direction the velocity of the passenger via pee And then we're trying to find via P primes the velocity of the passenger now relative to the water. Okay. And so the red line here is what we're trying to find so we can go ahead and write out what we have. We have V A P. Crime is equal to the vector velocity of the boat, plus vector velocity of the passenger. Okay, so if we pull again, everything we have, we find that this is equal to this would be 1.7 meters per second in thee. I have direction, Kim, plus 0.6 times the co sign of 45 degrees. Also in the I had direction plus well, that's gonna be in meters per second. So let's write under units. Well, actually, it's all gonna be in meters per second. Yeah, so let's go ahead. Right arm units, meters per second plus 0.6 Now, times signe the 45 degrees that's going to be in the J had direction. It's also meters per second. Okay, well, we can only add things together if they're in the light direction. So add the two. I had directions together, so 1.7 meters per second plus 0.6 times the coastline of 45 degrees. If you do that, that comes out to be 2.12 Like that direction. Great. And then 0.6 signed 45 degrees. Zero point for two. No, Jay had correction. No. And this is all in meters per second inbox setting because that's our solution.

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