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(II) A pilot performs an evasive maneuver by diving verti-cally at 310 $\mathrm{m} / \mathrm{s}$ . If he can withstand an acceleration of9.0 $\mathrm{g}$ s without blacking out, at what altitude must he beginto pull out of the dive to avoid crashing into the sea?

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$=1.1 \times 10^{3} \mathrm{~m}$

Physics 101 Mechanics

Chapter 5

Using Newton's Laws: Friction, Circular Motion, Drag Forces

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Applying Newton's Laws

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

Cornell University

University of Michigan - Ann Arbor

University of Washington

Simon Fraser University

Lectures

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

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01:55

So let me draw a nice little plane here. So that's Ah, good looking plane right here. To avoid crash, the pilot must, um, create a circle so that it can pull out. He can pull out of the night. So if let's say this red daughter line is the circle that the pilot has to form those Yeah, I don't want double lines. This is Well, um, so if the pilot wants to form this red dotted circular part, then, um, he must begin to form the circle at the height equal to the radius of the circle. So, basically, if the center is around here than this height, uh, defined by this red line must be equal to the radius of the circle. So, in other words, um, the centripetal acceleration E r, which is by definition v squared over r, must be equal to nine g. And from here, if we wantto get the height, that should be equal toe the radius. Or in our case, big r, so big are is equal to re squared over nine g and V is given as 310 meter per second squared there and then we have nine times 9.8 meeting for second squid. Combining them together, we see that our is 1.1 times and to the part three meters. So there's approximately 1100. That's approximately 1.1 kilometers till, uh, the pilot starts to form the circle. Thank you.

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