00:01
So we have a plan convex lens that has one flat surface and other with radius 15 .3.
00:09
So our is 15 .3 centimeters.
00:18
And we use this lens to view a red and yellow object that is 6 6 centimeters away from the lens.
00:27
And they gave us the index of refraction and we want to know the location of the image for the yellow and red.
00:34
So first we need to find the focal point for each of the spectre.
00:40
So we have that 1 over f red is index of refraction of red minus 1, 1 over r1 plus 1 over r2.
00:54
Because one of the lenses is flat lens, so this will be infinity.
01:00
So this term cancel.
01:01
So we got that fred using the value here as 1 .5106.
01:13
We got the fred this 36 .036.
01:18
And doing the same thing for the yellow one, the same radius.
01:24
The only thing that is different is that n yellow is 1 .526.
01:31
We got a focal point for yellow as 35 .209...