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(II) A potter is shaping a bowl on a potter's wheel rotating at constant angular speed (Fig. $51 ) .$ The friction force between her hands and the clay is 1.5 $\mathrm{N}$ total. (a) How large is her torque on the wheel, if the diameter of the bowl is 12 $\mathrm{cm} ?$ (b) How long would it take for the potter's wheel to stop if the only torque acting on it is due to the potter's hand? The initial angular velocity of the wheel is $1.6 \mathrm{rev} / \mathrm{s},$ and the moment of inertia of the wheel and the bowl is 0.11 $\mathrm{kg} \cdot \mathrm{m}^{2}$

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(a) 0.090 $\mathrm{m} \cdot \mathrm{N}$(b) 12$s$

Physics 101 Mechanics

Chapter 10

Rotational Motion

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

University of Michigan - Ann Arbor

Simon Fraser University

Hope College

Lectures

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

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A potter is shaping a bow…

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(II) A potter is shaping a…

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A potter is shaping a bowl…

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(II) A potter's wheel…

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A 34 -cm-diameter potter&…

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A potter's wheel is i…

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A potter's wheel is r…

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A potter's wheel with…

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A potter's wheel havi…

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A potter’s wheel having a …

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A clay vase on a potter&#x…

so we can draw a diagram of the system on the edge. Here we have the force. Friction on the direction of rotation would be clockwise. So we can say that for party. Ah, the torque exerted by the frictional force would be the torque tile. Equaling the frictional force times are, um times sign of data. Now hear the force of friction is assumed to be tangential to the clay, and so fada would be equaling 90 degrees, which would make the total torque for party equaling. You are times the force of friction times Sign of 90 degrees, which we know to be one. And so this would be equaling toe. Um, 1/2 times the diameter, 1/2 times 0.12 meters multiplied by the force of friction 1.5 Newton's. And this is equaling 0.90 Newton meters. This would be our answer. Four part, eh, Four part bead. We're trying to find the time t stop. The time to stop would be found from the angular, the final angular velocity equaling the initial angular velocity plus Alfa times T ah, we know that the total torque is equaling the moment of inertia times the angular acceleration. Uh, and and we know that the final angular velocity is going to be zero. And so we can say that the torque would be equaling. Ah, the essentially the negative initial angular velocity divided by Alfa. And so this would be equal to negative initial angular velocity, divided by the torque divided by the moment of inertia I And so this would be equaling negative 1.6 revolutions per second, multiplied by two pi radiance for every revolution. And then this is divided by negative 0.90 Newton meters. And then, of course, because the torque due to friction would be, um, opposite of the direction of motion. Therefore, the work would be negative and then divided by the moment of inertia. 0.11 kilograms, meters squared. And so we find that the time it takes to come to arrest would be approximately 12 seconds. This would be our answer for part B. That is the end of the solution. Thank you. For what

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