Question
(II) A sample of $\frac{233}{92} \mathrm{U}\left(T \frac{1}{2}=1.59 \times 10^{5} \text { yr) contains }\right.$ $7.50 \times 10^{19}$ nuclei. (a) What is the decay constant? (b) Approximately how many disintegrations will occur per minute?
Step 1
The decay constant is given by the formula $\lambda = \frac{0.693}{T_{1/2}}$, where $T_{1/2}$ is the half-life of the radioactive sample. Show more…
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(II) A sample of $^{233}_{92}$U ($T_\frac{1}{2} =$ 1.59 $\times$ 10$^5$ yr) contains 4.50 $\times$ 10$^{18}$ nuclei. ($a$) What is the decay constant? ($b$) Approximately how many disintegrations will occur per minute?
NUCLEAR PHYSICS AND RADIOACTIVITY
Half-Life and Rate of Decay
(II) A sample of ${ }_{92}^{233} \mathrm{U} \quad\left(T_{1}=1.59 \times 10^{5} \mathrm{yr}\right)$ contains $5.50 \times 10^{18}$ nuclei. $\quad(a)$ What ${ }^{2}$ is the decay constant? (b) Approximately how many disintegrations will occur per minute?
(II) A sample of $\frac{233}{92} \mathrm{U} \quad\left(T_{2}=1.59 \times 10^{5} \mathrm{yr}\right)$ contains $5.50 \times 10^{18}$ nuclei. $(a)$ What is the decay constant? $(b)$ Approximately how many disintegrations will occur per minute?
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