00:01
Now her in this question we are given that a simple pendulum that has a length of 0.3 m is a released from rest and at time t equals to zero.
00:12
The angle made with the vertical is 13 degree.
00:16
And we need to calculate the angle position of the pendulum at time.
00:23
T equals to 0.35 2nd.
00:28
And at time equals two 3.45 seconds.
00:35
And finally at time equals two six second.
00:43
No one is all the apart first and it was all this it will be forced calculating the angular speed of the pendulum.
00:51
And since the speculum is simple pendulum.
00:54
So oh my god that is, the angular speed is given by under root g.
00:59
Over l.
01:01
It's under root g.
01:02
We have actually the gravity and its value is 9.8.
01:08
Media per second squared divide by l.
01:12
Which is 0.3.
01:15
And on for the simplification we'll get the answer to be 5.71 radiant purse again.
01:22
So this is the angular speed where we can easily calculate the angler position of the pendulum at time equals two 0.35 seconds.
01:33
And it is given by theater.
01:35
Is the goals.
01:36
To think they are not times co sign omega teen.
01:42
So we're gonna plug the valleys here.
01:44
So take it out.
01:45
We have 13° times.
01:48
Cosine omega t.
01:49
Omega...