00:01
In this question, we have a xoidal wave that is traveling on the string in the negative x direction, and it has an amplitude of 1 centimeter.
00:13
It has a couple of parameters, so let's just try to write down the expression for it.
00:26
It has an amplitude of 1 .00 cm.
00:31
So let's say everything is in terms of centimeter.
00:35
That is, the amplitude is 1.
00:38
It's sinusoidal.
00:42
Then we have kx minus omega -t.
00:46
Except that it travels in negative x -direction.
00:48
So this is actually plus omega -t.
00:51
So weight plan is 3 centimeter.
00:55
So lambda equals 3 centimeter.
01:00
Amplitude equals 1 centimeter.
01:04
Dumbda equals 3 centimeters.
01:06
So k equals 2 pi.
01:08
Over lambda and this gives us what k is.
01:14
So last one it says the frequency f equals 245 hertz and we know omega equals to pi f and that gives us what omega is.
01:28
So ht equals zero, so particle string and x equals zero is displaced by a distance 0 .8 centimeters.
01:42
So what that is saying is that d, t equals 0, x equals 0 .8 centimeter.
01:55
So it's moving upward.
01:59
What that says, that is to say this actually there is a face difference in the sign.
02:10
Or another way to think about this is that it has, it may, also have an offset.
02:20
So it's possible that you also have something like this plus a constant...