In this case, the pulse travels twice the length of the cable (since it goes and returns), so $d = 2 \times 660 \, m = 1320 \, m$. The time taken is given as $t = 17 \, s$. Substituting these values into the formula gives $v = \frac{1320 \, m}{17 \, s} = 77.6 \,
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