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Problem 60 Medium Difficulty

(II) A source emits sound of wavelengths 2.64 $\mathrm{m}$ and 2.72 $\mathrm{m}$ in air. (a) How many beats per second will be heard? (Assume $T=20^{\circ} \mathrm{C}$ ) $(b)$ How far apart in space are the regions of maximum intensity?


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Related Courses

Physics 101 Mechanics

Physics for Scientists and Engineers with Modern Physics

Chapter 16

Sound

Related Topics

Periodic Motion

Mechanical Waves

Sound and Hearing

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Top Physics 101 Mechanics Educators
Christina Krawiec

Rutgers, The State University of New Jersey

Marshall Styczinski

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08:15

Sound and Light - Overview

In physics, sound is a vibration that typically propagates as an audible wave of pressure, through a transmission medium such as a gas, liquid or solid. In human physiology and psychology, sound is the reception of such waves and their perception by the brain. Humans can only hear sound waves as distinct pitches when the frequency lies between about 20 Hz and 20 kHz. Sound above 20 kHz is known as ultrasound and has different physical properties from sound below 20 kHz. Sound waves below 20 Hz are called infrasound. Different species have different hearing ranges. In terms of frequency, the range of ultrasound, infrasound and other upper limits is called the ultrasound.

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04:49

Traveling Waves - Intro

In physics, a traveling wave is a wave that propogates without a constant shape, but rather one that changes shape as it moves. In other words, its shape changes as a function of time.

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Video Transcript

limits. 2.64 meters, which I write is Lambda One and 2.72 meters, which I write his lame to to air A How many beats per second will be heard? Assume that the temperature is 20 degrees. That means that our velocity of Visa Bess is doing 43 meters per second Myth apart. Be how far apart in space or the regions of maximum minimum intensity. So how many beats per second will be heard? This is the, uh uh We can call this the frequency, Deke. Okay, well frequent to be f sub p. Uh, we're thinking right here is equal to So FCB for frequency B is equal to the difference between the two frequencies. Right? F one minus f two. We'll do the absolute value because we don't know which one's bigger. We just want to know the difference between the two. So absolute value of F one minus have to where the frequencies are equal to the speed of sound, divided, vital labeling. Well, the speed of sound is the same in both cases, so we'll pull that out front then. So we're now we're left with one over the wavelength, for each case is this is one over Lambda one minus, too. So if you plug in all the values we have here for the speed of sound for Lambda One Labor to and you do this calculation this comes out to be 3.82 hertz. Okay, this is part s O indicate this is part of a whole box set in now for part, Uh, for part B, we were asked to figure out how far apart in space are the regions of maximum in a minimum intensity. Okay, well, the speed of sound is Visa, Bess and the B frequency. We just found the reason to maximum minimum intensity or one beat wavelength apart. Okay, so we'll calculate the wavelength in of this. Be because that's how far apart they are called this claim to be this is going to be equal to, uh, the speed of sound. Oh, divided by the frequency. So we played those values in. We find that this is equal to 89.8 meters. Strawberry come boxes in their solution to part B

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In physics, a traveling wave is a wave that propogates without a constant shape, but rather one that changes shape as it moves. In other words, its shape changes as a function of time.

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