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(III) A factory whistle emits sound of frequency …

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Problem 69 Hard Difficulty

(II) A wave on the surface of the ocean with wavelength 44 $\mathrm{m}$ is traveling east at a speed of 18 $\mathrm{m} / \mathrm{s}$ relative to the ocean floor. If, on this stretch of ocean surface, a powerboat is moving at 15 $\mathrm{m} / \mathrm{s}$ (relative to the ocean floor), how often does the boat encounter a wave crest, if the boat is traveling $(a)$ west, and $(b)$ east?

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Physics 101 Mechanics

Physics for Scientists and Engineers with Modern Physics

Chapter 16

Sound

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Video Transcript

but they were asked to find how often the way encounters the crust. That means to find the time Peter, when the boat is traveling towards travelling west. So when the boat is traveling west, we have a boat. It's troubling. Rest. Um, we can write a frequency for the ocean where which is Ah, a prevalent off 44 meter 44 meter on da uh, speed off 18 meters per second. 18 meters per second. We can write it's, ah frequency by dividing its speed over the prevalent which will give us the frequency off zero point for mmm, mine herds for a boat which is moving towards the west for traveling uh, towards the west will encounter Ah, Doppler shift in frequency. That is, if dish for an observer will be which is moving towards source. So, um, several moving towards source is given by one plus, huh? Speed, often observer or the speed off there. The veil here, which cross parts to the speed off the sound in a Doppler formula. So I would like to meet us here times their frequency that is equal to by substituting the values, the speed of the observer. We have 15 while the speed off the whale, um, inside the station medium, which corresponds to the speed of sound in double a formula is 18 meeting per second time's the frequency we found it about, which is zero point four 09 This gives us the value off 0.7 50 hurts little hurts. And from here, we can find the time. Peter, which is t is equal to one where f so if I do right this value by one. The time Peter did I get here is 1.3 seconds. So in 1.3 seconds, um, the boat encounters there were crust. If the boat is traveling in the west, um, being guests in part B, If the boat is traveling towards east, we will do the same procedure. When the boat is traveling towards the east, then the observer moving away from the source. Then we can write the frequency. Also observer blowing away from the source we're from the source is equal to, um according to the Doppler formula is observer speed of the observer or the speed of the We're hearing this case which is times F and this will give us their frequency off zero point 06 it two hertz. And in order to find the time period, tea will do the same procedure by deriding one divided by F. We got here, so we'll do. I this f here and the time. Peter, here we get these, Uh, of 15 15 seconds. So here we get a time. Better off. 15 seconds. So 15 seconds. End off the problem. Thank you for

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Physics for Scientists and Engineers with Modern Physics

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Problem

(III) A factory whistle emits sound of frequency …

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Related Courses

Physics for Scientists and Engineers with Modern Physics

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Watch More Solved Questions in Chapter 16

Video Transcript

Douglas C. Giancoli

Physics for Scientists and Engineers with Modern Physics

Elyse Gonzalez

Christina Krawiec

Farnaz Mohseni

Jared Enns

This textbook answer is only visible when subscribed! Please subscribe to view the answer

Physics for Scientists and Engineers with Modern Physics

Elyse Gonzalez

Christina Krawiec

Farnaz Mohseni

Jared Enns

Douglas C. GiancoliPhysics for Scientists and Engineers with Modern Physics

Elyse Gonzalez

Christina Krawiec

Farnaz Mohseni

Jared Enns

Douglas C. Giancoli

Physics for Scientists and Engineers with Modern Physics