ii-according-to-a-simplified-model-of-a-mammalian-heart-at-each-pulse-approximately-20-g-of-blood-is

Name: ii according to a simplified model of a mammalian heart at each pulse approximately 20 g of blood is
Uploaded: 2019-05-10
Duration: 4 min 15 s
Channel: Numerade
Description: (II) According to a simplified model of a mammalian heart, at each pulse approximately 20 $g$ of blood is accelerated from 0.25 m/s to 0.35 m/s during a period of 0.10 s. What is the magnitude of the force exerted by the heart muscle?

Question

(II) According to a simplified model of a mammalian heart, at each pulse approximately 20 $g$ of blood is accelerated from 0.25 m/s to 0.35 m/s during a period of 0.10 s. What is the magnitude of the force exerted by the heart muscle?

Kathleen Tatem · Accepted Answer

Le Saux. We&#x27;re doing problem for in chapter four of wrinkly and it says that according to a simplified model of a mammalian heart, at each pulse, approximately twenty grams of blood is accelerated from point two five meters per second, two point three five meters for second during a period of ten seconds rest. What is the magnitude of the force exerted by the heart muscle? So as he was, write down all the information we&#x27;re given in the problem? So a mass to say twenty grams and, um standard issue Nissen&#x27;s kilograms. So this is also ah, good to convert right now. So don&#x27;t make him stick later like ten to the minus three kilograms. And we&#x27;re told that the the velocity of the blood is initially be zero. That&#x27;s what I&#x27;m calling it. I can, right as a subscript zero is zero point two five years per second and it&#x27;s final acceleration. Call out the F is zero point three five meters per second and the period of time, which I just called Delta t. The change in time we&#x27;re told, is your plane one zero seconds and for us to find the man shoot of the force exerted by the heart muscle so we can use Newton&#x27;s second law equals M. A. You know the mass, and we need to talk about the acceleration to use this equation. And we know that on average, the acceleration. It&#x27;s going to be the change in velocity over the change in time. Already given the change in time, Dr. T. We encountered a Delta V we were given, which is just the final velocity Mai esti initial velocity V zero so you can plug in those numbers. But we could really to see point three five minus point two five. And you&#x27;re just going to get near point one zero years for second. And A is going to be Delta V over Delta T. But Delta Bi and doesn&#x27;t tear both zero point one zero just racing here, right call sign So we can then dividing those two years going to get bagels. One Mir per second squared and so people&#x27;s M A. We&#x27;re just going to end up with twenty times ten to the minus three Noone&#x27;s, which is just the mass times a gal&#x27;s one you need to convert to the kilogram because the new things to find us a kilogram meter per second squared, so we can&#x27;t just use twenty grams to make sure you&#x27;re careful. Those unit conversions and you could also write this as point zero to new tenants, and that&#x27;s Ari.

Eric Mockensturm · Answer

we&#x27;re told that a simplified model of a mammalian heart, um each pulse approximately pumps approximately 20 kg, 20 kg 20 g of blood. Um and so that blood is accelerated from 0.25 m per 2nd, 20.35 m per second. And that all occurs in 1/10 of a second. So here we have our 20 g of blood. And so they want to know what the average of the magnitude of the force exerted by the heart muscle. Well, we can get an average acceleration, assuming that, you know, we have a uniform acceleration going from this velocity, this velocity over this amount of time. So we get an acceleration of one m per second squared. So that&#x27;s that&#x27;s a simple thing. And so they get the average force to accelerate this amount of mass by this amount, we just say the mass times acceleration. And that is winds up being 0.02 Newtons. Or we could say 20 million newtons or to santa Newton&#x27;s, I guess.

Eric Mockensturm · Answer

So we&#x27;re told that about 80 grams of blood is pumped when your heart beats. I&#x27;m in today a order. Um, blood starts at rest, assumedly and respect to and has a speed of about one meter per second. They go in the aorta. If the pumping takes your 0.17 seconds, we wonder if you know what the magnitude of the average force exerted on the blood is. All right. So we got a massive 80 kilograms of blood. It goes to arrest up to one meter per second over a time span of 0.17 seconds. The change in momentum is then zero point 08 kilograms meters per second. And the average force is the change in momentum over the change in time. And that turns out to be 0.47 Newtons.

Eric Mockensturm · Answer

We&#x27;re told that during each heart bank heartbeat, the mass of about 0.8 kilograms of blood is transported. I mean occurs over a time of 0.16 seconds and the blood, the blood transfer transitions from going 0.8 meters per second, up 0.8 meters per second down. So the change in velocity is 1.6 meters per second down and then they ask us what what is the average average acceleration? Well, that&#x27;s simply just the average velocity divided by the time the time change in time. But it started the change in velocity divided by the change in time, and we can just see that pretty much immediately. That&#x27;s 10 meters per second squared and again that is down.

Charles Carter · Answer

So this is just gonna use the formula. Our force is equal to U mass times acceleration. Okay, so it&#x27;s pushing 0.7 kilograms at a force 5.5 mutants. Okay, so in order to find a, we just divide 5.5 about 0.7 So the acceleration is gonna be 78.57 meters per second squared. That&#x27;s often a problem. Thank you, very

Averell Hause · Answer

so here the average acceleration in the ex direction would be equal to the change in velocity in the ex direction divided by the change in time. This would be equal to 1.0 meters per second minus zero meters per second and then divided by 00.250 seconds. And this would be equal to 4.0 meters per second squared. So this means that the correct answer would be answer choice D. That is the end of the solution. Thank you for watching.

Kathleen Tatem · Answer

for this problem, on the topic of dynamics were told that approximately 20 g of blood is accelerated from 0.25 m per 2nd, 20.35 m per second during a period of 0.1 seconds in a mammal&#x27;s heart, We want to find the magnitude of the force that is exerted by the heart muscle. Now the average acceleration of the blood, eh it was given by the final speed v minus the initial speed. We&#x27;re not over the time. T and that&#x27;s 0.35 m per second minus the initial speed of zero point 25 m/s, Divided by a time of 0.1 seconds. And so the blood undergoes an acceleration of one m per square second. The net force in the blood exerted by the heart is found from Newton&#x27;s 2nd law. This net force F is able to the massive blood times its acceleration, which is 20 g or 20 times 10 to the minus three kg times the acceleration of one m per square second, which gives the net force Exacted by the heart muscle to be 0.02. Newton&#x27;s

Kathleen Tatem · Answer

I know you have a question and this. It is given there Approximately 20. Our blood accelerates from 0.25 m purse again to 0.35 m purse again for 10 seconds. So we have to find a force. The force is always equal to mass into exploration. Some masks into the tu minus we even by teeth, So masses 20 times 25 1000 kg into veto is 0.35 meter purse. Again minus zero point. You will find meter per second And divided by time is 0.10 2nd. So this is 25 1000 everything in essay. So let us just leave the unit 0.10 x 0.10. Okay, this Juliet can float. So trolls will be equal to 0.02 newton&#x27;s. They should be the answer. Thank you.

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(II) Superman must stop a 120-km/h train in 150 m…

Problem 4 Easy Difficulty

(II) According to a simplified model of a mammalian heart, at each pulse approximately 20 $g$ of blood is accelerated from 0.25 m/s to 0.35 m/s during a period of 0.10 s. What is the magnitude of the force exerted by the heart muscle?

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0.02N

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