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(II) An aluminum sphere is 8.75 $\mathrm{cm}$ in diameter. What will be its change in volume if it is heated from $30^{\circ} \mathrm{C}$ to $180^{\circ} \mathrm{C} ?$

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$3.9 \mathrm{cm}^{3}$

Physics 101 Mechanics

Chapter 17

Temperature, Thermal Expansion, and the Ideal Gas Law

Temperature and Heat

Rutgers, The State University of New Jersey

Simon Fraser University

Hope College

University of Sheffield

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So now lemon names there is heated. Uh, it's Ari is 8.75 centimeters in diameter. What will be the change in volume if it is heated from 30 degrees Thio 180 degrees? Um, I say we go from our standard sort of for me left that the change of volume is equal. Thio on the current volume times a change in temperature ah times by the coefficient of volume expansion eso for aluminium Uh, gamma the is equal thio 75 times 10 to the minus six Obviously in this case Delta t his equal toe 180 minus 30 which is equal Thio hard. I should give this a unit here because that is important. So degree Celsius to the minus one dhoti is ah 150 in this case on So just a quick reminder The volume of the sphere is should know this But if he got in his 4/3 pi r cubed to regard a diameter So bracket B over to to give a radius cubed That s o if reception 8.75 in tow. Here we get a volume of 351 centimeters key so Essentially, this isn't a calculator. Gives us 351 centimeter cube on dhe on, then subsequently substituting these three values Hey into this equation up there. So the 351 times by 150 multiplied by 75 times 10 to the minus sets will give us Delta V is equal Thio three 0.94 centimeters cute.

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