Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

(II) An engineer estimates that under the most adverse expected weather conditions, the total force on the highway sign in Fig, 32 will be $\vec{\mathbf{F}}=(\pm 2.4 \hat{\mathbf{i}}-4.1 \hat{\mathbf{j}}) \mathrm{kN}$ acting at the cu. What torque does this force exert about the base $\mathrm{O}$ ?

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

$3.4 \times 10^{4} m \cdot N$

Physics 101 Mechanics

Chapter 11

Angular Momentum; General Rotation

Moment, Impulse, and Collisions

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

Simon Fraser University

McMaster University

Lectures

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

04:12

In physics, potential energy is the energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors. The unit for energy in the International System of Units is the joule (J). One joule can be defined as the work required to produce one newton of force, or one newton times one metre. Potential energy is the energy of an object. It is the energy by virtue of an object's position relative to other objects. Potential energy is associated with restoring forces such as a spring or the force of gravity. The action of stretching the spring or lifting the mass is performed by a force which works against the force field of the potential. The potential energy of an object is the energy it possesses due to its position relative to other objects. It is said to be stored in the field. For example, a book lying on a table has a large amount of potential energy (it is said to be at a high potential energy) relative to the ground, which has a much lower potential energy. The book will gain potential energy if it is lifted off the table and held above the ground. The same book has less potential energy when on the ground than it did while on the table. If the book is dropped from a height, it gains kinetic energy, but loses a larger amount of potential energy, as it is now at a lower potential energy than before it was dropped.

03:18

(II) An engineer estimates…

04:30

03:17

'An engineer estimate…

03:07

Three Force The body in Fi…

02:05

(II) A person exerts a hor…

02:37

Calculate the force (in ne…

02:01

Find the magnitude of the …

02:25

A person exerts a horizon…

01:30

The body in Fig. 10-31 is…

01:24

The force of $20 \hat{\mat…

04:57

01:15

The force $\mathbf{F}=\mat…

01:35

If the torque on a shaft o…

04:10

Answer the following quest…

we're gonna use Equation 11 3 B In order to find the torque, the torque vector is gonna be equaling. Yeah, cross product between our and affect er's. And then this would be equaling. I had Jay had K hat 8.0 6.0 on plus or minus 2.4, minus 4.10 And so this would be killing Newton's. The units would be killer Newton's meters, and so the torque vector would be equaling. Essentially, we can say I had this would be time six point negative, 6.0 times negative 4.1 and then plus J hat times 6.0 times plus or minus 2.4. Plus que hat times negative 8.0 times cross remind us 2.4 and then this would be the units would again be killer Newton's meters, so the torque factor is then equaling 2.5 i hat. This would be plus or minus 1.4 j hat plus or minus 1.9 K hat, and this would be times 10 to the fourth Newton meters. This would be our answer in ah unit vector form, and then If you want to find the magnitude, we could simply say that the magnitude of the torque factor is equaling. The square root of 2.46 will round at the very end, 2.46 squared plus 1.44 squared plus 1.9 to quantity squared. And this would be again times 10 to the fourth Newton meters, and we find that the magnitude of the torque factor is equaling. This would be 3.4 times 10 to the fourth Newton meters. This would be our magnitude of the torch factor and our final answer. That is the end of the solution. Thank you for one.

View More Answers From This Book

Find Another Textbook