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(II) At the instant a race began, a 65-kg sprinter exerted a force of 720 N on the starting block at a 22$^\circ$ angle with respect to the ground. ($a$) What was the horizontal acceleration of the sprinter? ($b$) If the force was exerted for 0.32 s, with what speed did the sprinter leave the starting block?

a) $10.27 \mathrm{m} / \mathrm{s}^{2}$b) $3.286 \mathrm{m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 4

DYNAMICS: NEWTON'S LAWS OF MOTION

Section 7

Solving Problems with Newton's Laws: Free-Body Diagrams

Newton's Laws of Motion

Applying Newton's Laws

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So we have the mass. We have Ah, runner. So this represents the runner. We have a force normal. We have a force of gravity and at an angle of Seita we have a force applied. He's pushing off the starting block with a certain amount of force. So in order to fund his acceleration, you can say Sigma F in the ex direction equals M A and the extraction. And this simply equals force applied coastline of data. You know that Ace of X equals force applied Cho san its data and then this would be divided by am and we can actually solve. So it will be seven. Twenty co sign of theta here It's going to be twenty two degrees divided by mass or of sixty five telegrams and we find that the acceleration is going to be a ten point two seven meters per second squared. And to find the fun of velocity, we simply have the initial close eighty. We know that of the initial zero, so we can simply say the acceleration ten point two seven times the duration of the force applied. So I'll be point three two and this will be three point two eight six meters per second. So this will be your answer for this final speed. And this will be Eric's answer for the acceleration. That is the end of the solution. Thank you for watching.

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