00:01
Okay, so this problem gives us the, that we're using potassium.
00:07
It has an initial decay rate of that, and then we have its half -life, and then our goal is to get the mass of the sample.
00:16
And so i'm going to go ahead and write out these givens.
00:20
So r is equal to 2 .05 times 10 to the 5, oops, not 2 .05, just plain 2 .05.
00:30
2 .0, 10 to the 5.
00:36
Inverse seconds.
00:39
And then i also want to write down the molar mass of potassium that isotope.
00:46
So we'll use that later, 39 .964 grams per mole.
00:58
And yeah, so now i think i'm ready to go.
01:01
So basically, the initial activity rate, i hope this is, the book somewhere, but it's just the initial number times lambda, and you get that from taking a derivative of n equals n -e -e -to -the -minus t -lam, and evaluating it time equals zero.
01:19
And so therefore, n -not is equal to r -not divided by lambda.
01:26
And then we know lambda is the l -n of two times divided by the half -life.
01:37
So times divided by t one -half.
01:39
Oh yeah, and i'll go ahead and put t -1 -half up here.
01:43
And when i look that up, it was 1 .265 times 10 to the nine years.
02:05
Okay.
02:07
So now to continue this calculation, so we just want to plug in our r not, which is this.
02:15
And then t1 .5, and you also want to convert that to years.
02:20
So i guess i'll just go ahead and write down what i put in my calculator.
02:25
So 2 .0.
02:26
Oh, wow.
02:29
Actually, i'm going to just copy and paste what i put into my calculator to get the first part.
02:39
Okay.
02:49
These numbers are so long in this section...