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(II) Consider the point $x=1.00 \mathrm{m}$ on the cord of Example 5 of "Wave Motion." Determine $(a)$ the maximum velocity of this point, and $(b)$ its maximum acceleration. (c) What is its velocity and acceleration at $t=2.50 \mathrm{s} ?$

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a) 41 m/sb) $6.4 \times 10^{4} m/ s^{2}$c) 35 m/s $3.2 \times 10^{4} m / s^{2}$

Physics 101 Mechanics

Physics 102 Electricity and Magnetism

Chapter 15

Wave Motion

Periodic Motion

Mechanical Waves

Electromagnetic Waves

Cornell University

Rutgers, The State University of New Jersey

McMaster University

Lectures

03:40

In physics, electromagnetic radiation (EM radiation or EMR) refers to the waves (or their quanta, photons) of the electromagnetic field, propagating (radiating) through space, carrying electromagnetic radiant energy. It includes radio waves, microwaves, infrared, (visible) light, ultraviolet, X-rays, and gamma rays. Electromagnetic waves of different frequency are called by different names since they have different sources and effects on matter. In order of increasing frequency and decreasing wavelength these are: radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays and gamma rays.

10:59

In physics, Maxwell's equations are a set of partial differential equations that, together with the Lorentz force law, form the foundation of classical electromagnetism, classical optics, and electric circuits. They underpin all electric, optical and radio such electromagnetic technologies as power generation, electric motors, wireless communication, cameras, televisions, computers, and radar. Maxwell's equations describe how electric and magnetic fields are generated by charges, currents, and changes of these fields. The equations have two major variants. The microscopic Maxwell equations have universal applicability but are unwieldy for common calculations. They relate the electric and magnetic fields to total charge and total current, including the complicated charges and currents in materials at the atomic scale. The macroscopic Maxwell equations define two new auxiliary fields that describe the large-scale behaviour of matter without having to consider atomic scale details. The equations were published by Maxwell in his 1864 paper "A Dynamical Theory of the Electromagnetic Field". In the original paper Maxwell fully derived them from the Lorentz force law (without using the Lorentz transformation) and also from the conservation of energy and momentum.

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the question off traveling there is given. He's given 0.26 Sign off 45 x minus 1570 p plus 0.66 Now in party, we have to find the maximum velocity. We know that the velocity equation will be equal toe partial differentiation off displacement function with respect to time. So this will be equal toe minus 15 70 into 0.0 26 cause off 45 minus 1570 t plus 0.66 This is the equation for velocity in leave. Now the maximum velocity will be equal to weaken diet 1570 and 20.26 So the value off next velocity will be equal to around 41 m per second. Now the maximum exploration we know that exploration function will be equal toe partial differentiation, off velocity function with respect to times. So we get after differentiating velocity function with respect to time differentiation. Off this function with respect to time we get the acceleration function will be equal to 1570 Squire in 20.26 in the sign 45 x minus 15. 70 T plus 0.66 This is the exclusion function. Now the maximum velocity. Sorry. Exploration. The maximum acceleration will be equal toe 1570 Squire in tow. 0.26 So this will be equal to 6.4 into 10 to the power four. We did What's taking the square? This is the answer. 45 B. Now we have to find in part C the velocity and acceleration at equal toe 2.50 seconds. So we will put the X when we did and time 2.50 2nd in the the lost city function. So we get the value off velocity into shine. So he calls, Yeah, 45 x, which is one mind is 1570 and two p which is 2.50 Let's see the 0.66 So we get the value off. The speed is equal to 35 m per second. Now for excavation again, we put X is equal to one and P is equal to 2.50 in the acceleration equation. So we get value off acceleration 1570 square do 0.26 into sign 45 X, which is one minus 1570 in tow. T which is 2.50 less. 0.66 So the value off acceleration will be equal to. By calculating this, we get 3.2 into 10 to the power four. We did that second square. So this is the acceleration at X is equal to one and P is equal to 2.50 And this is the velocity.

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