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(II) Determine $(a)$ the work done and $(b)$ the change ininternal energy of 1.00 $\mathrm{kg}$ of water when it is all boiled tosteam at $100^{\circ} \mathrm{C}$ Assume a constant pressure of 1.00 atm.

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a. $\approx 1.72 \times 10^{5} J$b. $2.09 \times 10^{6} J$

Physics 101 Mechanics

Chapter 19

Heat and the First Law of Thermodynamics

Kinetic Energy

Potential Energy

Energy Conservation

Temperature and Heat

Thermal Properties of Matter

The First Law of Thermodynamics

The Second Law of Thermodynamics

Cornell University

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

Simon Fraser University

Lectures

03:23

In physics, mechanical energy is the sum of the kinetic and potential energies of a system.

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In physics, the kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. The kinetic energy of a rotating object is the sum of the kinetic energies of the object's parts.

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(II) Determine $(a)$ the w…

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Water is boiled at $100^{\…

So we have one kilogram off water and we have boiled it off 800 messages. Now we want to find out the amount of working. Obviously, the amount of work done is PW at constant pressure. So we simply need to find the change in volume. So we have water which can work. Got kind of already do water vapor, which is a gas. So we'll consider that this water vapor is an ideal gas for the sake of this problem. So water is simply mass derided by density. So masses one kilogram on. We know that the density off water is one kilogram per leader. So that's 10 cubed kilograms were a meter cubed. So that's 10 baht minus three. Meet a cute on the wall. You want the water vapor because it's ah, an ideal guess we was the formula and our tea by v. I'm sorry. Anarchy by people. The number off to find the number of votes of water we use, uh, we divide the mass of water by the molar weight of water multiplied by Artie annually by pressure. The mass of water is one kilogram. The bowler muscle water is 0.18 grams, which is 0.18 kilograms. Times are is a 0.314 chul for mole Kelvin jewels. For more, Calvin finds the temperature is 100 degrees Celsius, but do not forget to convert it into Kelvin, which is 3 73 killers. Divide by pressure, which is one atmosphere, which is 1.1 into 10. Q. I'm sorry. Tend Bar five passports. Now this don't start to be 1.70 major. Cute. If you notice this. This is a very large volume compared to this. For you, it's almost someone did it 1700 times larger, which means we can simply consider the initial Placido. So work is speed, and maybe this is part of a, by the way. So that's pressure, which is one atmosphere, which is 1.1 into tend bar for passports. Times The change in volume is 1.70 meters square after meter. Cute. This sends out the week 1.72 into 10. Part five. Jules, this is the amount off work. Then buy the gas. No, for Bobby. We want to find out the change in the internal energy to do that. We know that the change in internal energy is Q minus. W accused the amount of heat added on what abused worked on the gas. So we simply need to find a lot of heat at it on to boil the water. The amount of heat Oh added simply mass times elated. Hit off authorization. The mask is one kilogram times delayed and hit off. Authorization is 2260. Hello, Jules. What you looking at? It's to find doing. Want to into 10.6 jewel per kilogram if you want to read it that way on distance or to be 2.26 into 10 parts. Six. Jules. Therefore, the change in internal energy is Kiwanis W, which is to 1 to 6 into 10. Parts six. Minus 1.72 into $10 5 It stands out a way to 50.9 into 10 parts. Six. Jules. This is the change in internal energy. Off water. It's 2.0. That's it.

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