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(II) Determine the net torque on the 2.0 -long uniform beam shown in Fig. $50 .$ Calculate about $(a)$ point $C$ , the $\mathrm{CM}$, and $(b)$ point $P$ at one end

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(a) $17 \mathrm{m} \cdot \mathrm{N}$(b) $-10 \mathrm{m} \cdot \mathrm{N}$

Physics 101 Mechanics

Chapter 10

Rotational Motion

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

Rutgers, The State University of New Jersey

University of Washington

Simon Fraser University

University of Winnipeg

Lectures

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

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Determine the net torque …

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(II) Determine the net tor…

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30. (II) Determine the net…

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1. Determine the net torqu…

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"29. (II) Determine t…

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Calculate the net torque (…

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Calculate the net torque a…

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A uniform beam of mass $M$…

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$\cdot$ Calculate the net …

So this is the figure from the question. We need to find the torque about point C so we can say that for a he torqued about point C is going to equal. Ah, before we actually label this, we need to specify direction. To be positive. We're going to say that counterclockwise, I would be considered positive once we have specified the direction that is considered positive. We can then evaluate the torque so that work about Point C would be equal to negative 1.0 meters multiplied by that 56 Newton force at the top times sign of 30 degrees. This would be a plus 1.0 meters times 52 Newton force at the bottom times again sign of 60 degrees. This is giving us 17 Newton meters. The fact that this torque is positive means that this direction of motion would be counter clockwise or the other than that torque would be counter clockwise. And for part B, we want to find the torque about Point P, and this would be equal to negative 2.0 meters multiplied by 56 Newtons times again sign of 30 degrees and then we'll be plus 1.0 meters times that 65 Newton Force times sign of 45 degrees. This is giving us negative 10 Newton meters. The fact that this is negative means that, um 10. Sorry, 10 10 points. 10 point means that this zero is significant s so we can say again, this is two significant figures. One and zero came The fact that it's his negative means that this would be a clockwise Twerk because we chose counterclockwise to be positive. That is the end of the solution. Thank you for watching.

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