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(II) Estimate the frequencyof the sound of the ocean when you put your ear very near a $20-\mathrm{cm}$ -diameter seashell (Fig. 34).

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430$H z$

Physics 101 Mechanics

Chapter 16

Sound

Periodic Motion

Mechanical Waves

Sound and Hearing

Cornell University

University of Washington

Hope College

University of Sheffield

Lectures

08:15

In physics, sound is a vibration that typically propagates as an audible wave of pressure, through a transmission medium such as a gas, liquid or solid. In human physiology and psychology, sound is the reception of such waves and their perception by the brain. Humans can only hear sound waves as distinct pitches when the frequency lies between about 20 Hz and 20 kHz. Sound above 20 kHz is known as ultrasound and has different physical properties from sound below 20 kHz. Sound waves below 20 Hz are called infrasound. Different species have different hearing ranges. In terms of frequency, the range of ultrasound, infrasound and other upper limits is called the ultrasound.

04:49

In physics, a traveling wave is a wave that propogates without a constant shape, but rather one that changes shape as it moves. In other words, its shape changes as a function of time.

00:47

Estimate the frequency of …

01:30

04:00

(III) The human ear canal …

01:55

01:02

Some studies indicate that…

02:16

03:57

The size of your eardrum (…

04:39

The human ear canal is app…

02:13

(II) A sailor strikes the …

An oceanic depth-sounding …

02:12

The bulk modulus of seawat…

01:52

Estimate the length of you…

05:00

You're underwater, lo…

02:34

Do not stick anything into…

It wants us to estimate the frequency of the sound of the ocean when you put your ear very near to a 20 centimeter diameter shell. So if you put your ear nearly shell, it sounds like the sound of a notion. So it wants us to understand estimate the frequency of that sound near this 20 centimeter diameter shell. So I wrote down what we're given here, and that's that The shell was 20 centimeters in diameter. Well, 20 centimeters, 0.20 meters and we want to use S I units. Um and that's I found that because there's 100 centimeters and every meter. Okay, So, um, to calculate the fundamental frequency, we're going to write that the frequency is equal to the velocity of sound divided by the way of life. Okay, well, the wavelength here. In order for this to be a resonant frequency here, um, it's going to have to be the length or I'm sorry. Thea diameter was equal to 1/4 the wavelength core. The wavelength is four times that diameter when we know the diameter. So now we can do this calculation because the speed of sound in this medium there will write this up here. So we know what this is is 343 meters per second. We have everything in the equation. We need to make the calculation. Okay, so you plug in 343 meters per second for the speed of sound. Um, and you plug in four times the diameter, which is 0.20 meters for the numerator of the, um the denominator of this equation and this comes out to be 429. Hertz, go. Oh. Okay. Well, if you look at the value we were given 0.20 meters. That has two significant figures, so we can't report higher than two significant figures. So we read. Rewrite 429 hertz. I have two significant figures. So we round up to 430 hertz weakened box that in as your solution. Clear question.

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