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(II) How many revolutions per minute would a $22-\mathrm{m}-$diameter Ferris wheel need to make for the passengers tofeel "weightless" at the topmost point?

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$$9.0 \mathrm{rpm}$$

Physics 101 Mechanics

Chapter 5

Using Newton's Laws: Friction, Circular Motion, Drag Forces

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Applying Newton's Laws

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

Rutgers, The State University of New Jersey

Simon Fraser University

Hope College

McMaster University

Lectures

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

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(II) How many revolutions …

03:56

01:41

How many revolutions per m…

02:49

03:53

A Ferris wheel with a radi…

02:42

(II) At what rate must a c…

02:29

02:17

(Ferris wheel) You are on …

01:39

Ferris Wheels A neighborho…

03:26

and this problem, we have to calculate the angler velocity of the Ferris wheel to make for the passengers to feel were less What the angle of lost two of the fairest will is, uh, Omega. Also, the passengers will feel the word lists at a point where the force off gradation will be compensated by the centrifugal force. Also, we can ride the condition for this worthless is and we square divided by our is equals to mg. So in this engine is the weight off the passenger. And this is the centrifugal force experienced by the passenger. From here, we can wide this we as well as equals toe squared off our G and then we can define omega is omega is equals toe redivided by our now by inserting value or free into the square. And we can write omega omega is equals to squared off G divided by ah, their school. That equation about one. No. By inserting values into this equation, we can white. Oh my God, Is it omega is equals two squared off G, which is equals to 9.81 m per second squared. Divided by R Is the radius off the Ferris wheel. Also can we can write This are in terms of diameter as a diameter is 22 m divided by two Because you know they're disarrayed. Assume V equals two diameter, divided by two. So from here, we can write the value for this Omega is Omega is equals to zero point my full for radiant per second. Since we know that two pi radiance is equals to one revolution and one second is equals to one divided by 60 times off. One minute. Using these convergence, we can write the omega as it omega is equal to 9.0 our revolution permanent. So this is the required angler. Velocity off the very sweet Thank you.

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