00:01
Entropy of the water, we can say that this is going to be equal to the heat transfer associated with the water, divided by the temperature at which it occurs.
00:08
This will be equal to the mass of the water, multiplied by the latent heat of vaporization, divided by t.
00:15
We can solve and say that this is going to equal 0 .45 kilograms, multiplied by 2 .26 times 10 to the 6th joules per kilogram.
00:30
And then this will all be divided by the boiling temperature of water, 373 kelvin.
00:37
Therefore, the change in entropy of the water is going to be equal to 27, 27 joules per kelvin.
00:44
So 2 ,727 joules per kelvin.
00:48
Now for part b, the change in entropy of the surroundings, we are going to assume that all of the heat that the water absorbs comes from the surroundings.
00:57
So essentially it'll just be negative, negative one times the change in entropy of the water, which would of course be equal to negative 2 ,727 joules per kelvin.
01:09
And again, this is assuming that all of the energy comes from the environment.
01:14
For part c, they want the change in entropy of the universe.
01:17
So this would be equal to the change in entropy of the water plus the change in entropy of the surroundings...