00:01
To solve this problem we will use equation 11 .13c for the precisional angular velocity, which will be given by mgr over i omega, where r is now the center of mass of the combination, combination of the wheel and the additional mast that is placed on the axis of rotation.
00:35
Now since the mass, which is half of the mass of the wheel, is placed on the axis of rotation, so it does not contribute to the total moment of inertia.
00:50
So moment of inertia due to this mass about the axis of rotation is zero.
00:58
Therefore, the total moment of inertia will still be same and will be equal to that of the wheel, which is m r square.
01:14
Assuming the wheel is a circle now.
01:19
But we don't need this expression now.
01:21
So let's forget about that.
01:23
And let's just call the moment of inertia, the total moment of inertia equal to the moment of inertia of the wheel.
01:37
Now the addition of the mass does not change the center of mass, but it does change the total mass which is now equal to mass of the wheel plus the mass that is placed on the axis of rotation, which is m over 2.
01:58
So the total mass is now 3m over 2.
02:04
Now let's find the center of mass.
02:13
So r will now be equal to, so we will use this formula for the center of mass.
02:26
So m1 is the mass of the wheel, so that is m, x1, which is the distance of the wheel from the axis of rotation, so that is l over 2, the radius...