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(II) In Fig. 9 assume the distance axis is the $x$ axis and that $a = 10.0 \mathrm { m }$ and $\mathrm { b } = 30.0 \mathrm { m }$ . Estimate the work done by this force in moving a 3.50 -kg object from a to b.

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$$=\quad 2800 \mathrm{J}$$

Physics 101 Mechanics

Chapter 7

Work and Energy

Work

Kinetic Energy

Potential Energy

Energy Conservation

Cornell University

Hope College

University of Sheffield

University of Winnipeg

Lectures

04:05

In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

03:47

In physics, the kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. The kinetic energy of a rotating object is the sum of the kinetic energies of the object's parts.

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02:22

7.39. So we have this figure here and we want to estimate the work that's done by the force that spotted here are the the force times the coast sine of the angle between the forces direction and displacement Uh, moving an object with a given mass from point A to point B. Now, of course, the mass actually doesn't turn out to be relevant at all because the the work is the integral of f dot d x. So unless the force depended on the mass, somehow it's not really relevant. Certainly the displacement doesn't depend on the man mass, at least one, at least when both of those things were given to us. So we just take This is ah, sort of ah re mance, um, with rectangles of finite wigs. So there are seven segments here over a distance of 20 meters and Delta X, some by is the same for all values of high. So this convinced factor out. And so we take the value of the force at the centre of each rectangle, sort of having toe eyeball it a little bit 175 Newton's That's 125 plus 110 Newtons plus 100 minutes plus 95. And so this is huh? 20 divided by seven times 985 Newton meters, which is a fool. So them just multiplying those together we get 2800 jewels.

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