Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

(II) In working out his principle, Pascal showed dramatically how force can be multiplied with fluid pressure. He placed a long, thin tube of radius $r=0.30 \mathrm{cm}$ vertically into a wine barrel of radius $R=21 \mathrm{cm},$ Fig. $50 .$ He found that when the barrel was filled with water and the tube filled to a height of $12 \mathrm{m},$ the barrel burst. Calculate $(a)$ the mass of water in the tube, and $(b)$ the net force exerted by the water in the barrel on the lid just before rupture.

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

a) 0.34 $\mathrm{kg}$b) $1.6 \times 10^{4} \mathrm{N}$

Physics 101 Mechanics

Chapter 13

Fluids

Fluid Mechanics

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

University of Sheffield

Lectures

03:45

In physics, a fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases, plasmas and, to some extent, plastic solids.

09:49

A fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases and plasmas. Fluids display properties such as flow, pressure, and tension, which can be described with a fluid model. For example, liquids form a surface which exerts a force on other objects in contact with it, and is the basis for the forces of capillarity and cohesion. Fluids are a continuum (or "continuous" in some sense) which means that they cannot be strictly separated into separate pieces. However, there are theoretical limits to the divisibility of fluids. Fluids are in contrast to solids, which are able to sustain a shear stress with no tendency to continue deforming.

04:45

Constantworking out hi…

05:01

Here is a demonstration Pa…

04:53

Pascal placed a long 0.20-…

02:31

05:09

A wooden barrel full of wa…

01:56

There is a story about Pas…

03:31

Water is poured into a lar…

05:05

A circular wine barrel 75 …

02:08

A crass host pours the rem…

01:03

In Fig. $14-32,$ an open t…

06:36

A piston pushes $20^{\circ…

05:43

so here for part A, the mass is simply gonna be equal to the density times the volume. And this is gonna be what's the density times pi r squared the cross sectional area times the height and at this point, we can just solve. So this will be 1000 kilograms per cubic meter. Times 9.8. Rather my part of my apologies, not 9.1000 kilograms per cubic meter times pi rather times r squared. So 0.3 uh, meters squared and then times the height of 12 meters and we find that the mass is gonna be equal to a 0.339 kilograms. So this would be your answer for part. Hey, and then for part B. Ah, we want to find the force that is on the lid and the force on the lid is gonna be equal to the gauge pressure times wth Ekran sectional area of the lid. So this would be equal to the density times, the gravity, the acceleration due to gravity times the height, times pi r squared and then we can solve. So the force on the lid I would be equal to 1000 times 9.8 times 12 meters times pi times point to one meters. Quantity squared and the force on the lid is going to be equal to 1.6 times 10 to the fourth Newton's. So this would be our final answer for Part B. That is the end of the solution. Thank you for watching.

View More Answers From This Book

Find Another Textbook

Simon Fraser University

McMaster University