00:01
It is observed that 55 .5 mil of water at 20 degrees celsius completely fills a container to the brim.
00:10
When the container in the water heated to 60 degrees celsius, 0 .35 grams of water is lost.
00:20
What is the coefficient of volume expansion of the container and what is the most likely material of the container? density of water at 60 degrees celsius is 0 .98 3 to 4 grams per milliliter.
00:34
So our initial equation that we're going to start from is delta v.
00:42
So change in volume is equal to a coefficient of volume expansion times a change in temperature multiplied by the initial volume.
00:58
So if we just heat 55 .5 milliliters of water at 20 degrees to 60 degrees, our change of volume will be given by delta v, let's call this, delta v water for clarity, is equal to a coefficient of volume expansion, which is given in the table or look it up.
01:28
210.
01:30
So in this case, b is 210 times 10 to minus 6.
01:34
So 210 times 10 to the minus 6.
01:39
And the change temperature of 60 minus 20 is equal to 40.
01:47
And the initial volume is 55 .5.
01:53
So times 55 .5.
01:55
And from that, if we plug that in, we get 0 .466.
02:01
So is equal to 0 .466 milliliters...