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(II) On an ice rink two skaters of equal mass grab handsand spin in a mutual circle once every 2.5 $\mathrm{s}$ . If we assumetheir arms are each 0.80 $\mathrm{m}$ long and their individual massesare $60.0 \mathrm{kg},$ how hard are they pulling on one another?

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$=303.19 \mathrm{~N}$

Physics 101 Mechanics

Chapter 5

Using Newton's Laws: Friction, Circular Motion, Drag Forces

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Applying Newton's Laws

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

Rohan S.

April 7, 2020

There is 100 N of gravitational force between two objects. If these are moved so that they are now twice as far apart, what is the new gravitational force between them.

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University of Michigan - Ann Arbor

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In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

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So we have two skaters holding hands and their arms are about 0.8. So we're gonna use that as the radius of the circle that they're spinning in and were asked to solve for the force acting on each of the ex skaters. So they are rotating one revolution every 2.5 seconds. So we can also say that that 2.5 seconds is the here Ian and we want to solve for our velocities or velocity is going to be our circumference divided by the period. So too high times 0.8, divided by 2.5 seconds, gives us a velocity of about 2.1 meters per second. And if we look at just one of the ice skaters, they only have the force of the other ice skaters exerting on them as our centripetal force. So that force is just the mass of one of the skaters. Times velocity squared over r into centripetal acceleration so we can say 60 times 2.1 squared, divided by the point. Eat gives us a force of 303.19 minutes, and Newton's Third Law tells us that the other ice skater experiences the same force in the opposite direction.

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