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(II) On an ice rink two skaters of equal mass grab hands and spin in a mutual circle once every 2.5 s. If we assume their arms are each 0.80 m long and their individual masses are 55.0 kg, how hard are they pulling on one another?

$2.8 \times 10^{2} \mathrm{N}$

Physics 101 Mechanics

Chapter 5

CIRCULAR MOTION; GRAVITATION

Section 1

Kinematics of Uniform Circular Motion

Dynamics of Rotational Motion

Gravitation

Cornell University

University of Winnipeg

McMaster University

Lectures

03:55

In physics, orbital motion…

02:21

In physics, rotational dyn…

01:55

(II) On an ice rink two sk…

02:50

On an ice rink, two skater…

01:54

Two ice skaters stand at r…

02:27

Twin skaters approach one …

03:00

Two ice skaters, with mass…

06:26

Two ice skaters have masse…

02:52

Two skaters, one with mass…

17:05

Two figure skaters, one we…

04:10

$\cdot$ Two figure skaters…

04:00

Skating Two skaters of une…

02:47

Two people of equal mass a…

02:03

A 52-kg ice skater spins a…

04:04

Two skaters collide and gr…

06:02

09:34

Force on a skater's w…

01:26

(II) Two objects attract e…

04:47

05:30

ssm mmh Two friends, Al an…

0:00

A 55.0-kg ice skater is mo…

time period. Capital T is given us 2.5 seconds and we know that these equal do two fired wide variety. This is the velocity. And we know that the fourth one person is exciting on the another person is equal to m v squared. Why are there s m is 55 Killing velocity is two pi r divided by T whole square guarded by our which is 0.80 Yet now putting the value off are nt value Off force is equal toe by our which is 0.80 t 2.5. It's quiet. The value of force is equal. Do 27 eight Newton or we can say 2.8 10 to the power to Newton. This is the value of force accepted by the one person to the and all of person.

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