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(II) Particles of charge $+ 75 , + 48 ,$ and $- 85 \mu$ Care placed in a line (Fig. $52 ) .$ The center one is 0.35 from each of the others. Calculate the net force on each charge due to the other two.

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$\vec{F}_{+75}=-150 N \hat{i}$$\vec{F}_{+48}=560 N \hat{i}$$\vec{F}_{-85}=-420 N \hat{i}$

13:15

Ceren Uzun

Physics 102 Electricity and Magnetism

Chapter 21

Electric Charge and Electric Field

Gauss's Law

Brian A.

April 10, 2021

Particles of charge +65,+48 and -95 Care placed in a line (Fig. The center one is 0.35 from each of the others. Calculate the net force on each charge due to the other two.

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

Hope College

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articles of charge 75 48 negative 85 micro columns are placed in a line as shown in the figure in your textbook. The Center one is .35 from each of the others Calculate the net force on each charge due to the other two. Okay, so so you have, oh wait, Okay, so the 75 charges on the left, The 48 is in the middle and the -85 is on the right. And these are micro columns. So the force on, let's call this one, number one, number two and number three. So first one onto is K Q one Q 2 over R squared. In this case they tell us that This distance is .35 m. All of these charges are in units of micro. Cool. Um, so 10 to the -6 schools and Columns constant is approximately nine times 10 to the 9th. Okay, so plugging in values, this gives us a force of 200 and 60 five newtons And then force one on 3 Is ke ke one Q three over R squared. But in this case the distance is two times 0.35 since it's going twice that distance. So Force one on 3 Is 117 Newton's. So subtracting these to 65 -117 Is 148 New. So the net charge on charge one due to the other two charges Is 148 Newtons. And it's to the left. Okay, so looking at The net force on the negative 85 micro Coolum due to the 48. So it's 4 3 on two is K Q three Q two over R squared. In this case are is 20.35 And we get 300 newtons then force three on one. KQ one Q 3 over this distance is two times 0.35 squared, Which is 117 Newton's. So that means for three is equal to their both pointing in the same direction. So you add them. Let me get 417 newton's. And for the last set You're looking at one or 2 into on three Is KQ one Q 2 over R squared. And we get 265 newtons Evan K q two Q three over R squared. And this is 300 Nunes. So forced to is 500 And 65 Newtons. This one is to the right.

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