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(II) Rain is falling at the rate of 5.0 $\mathrm{cm} / \mathrm{h}$ and accumulates in a pan. If the raindrops hit at 8.0 $\mathrm{m} / \mathrm{s}$ , estimate the force on the bottom of a 1.0 $\mathrm{m}^{2}$ pan due to the impacting rain which does not rebound. Water has a mass of $1.00 \times 10^{3} \mathrm{kg}$ per $\mathrm{m}^{3}$ .

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0.11$N$

Physics 101 Mechanics

Chapter 9

Linear Momentum

Motion Along a Straight Line

Kinetic Energy

Potential Energy

Energy Conservation

Moment, Impulse, and Collisions

Cornell University

Rutgers, The State University of New Jersey

Simon Fraser University

Lectures

04:05

In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

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In physics, the kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. The kinetic energy of a rotating object is the sum of the kinetic energies of the object's parts.

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Okay, so does Chapter nine. Problem 27. So says rain is falling at the rate of five centimeters per hour in accumulates in a picture. If they're raindrops hit at a media's for a second estimate the force on the bottom of a one square meter pan due to the impacting rain which does not rebound. And it also says water has a massive 1000 kilograms per square meter. Okay, so if the final if the rain is not a rebound and we know that the final speed is zero of rain, so we can find the average force as the impulse or change in momentum over the time contact here So we can write this as in if, I know minus and the initial over Delta T. But we just said the final equals zero. So this is the same as negative in the initial over Delta T. Okay, so now what we can do is we can write the mass in terms of the volume and intensity. This becomes the density times the volume that was the initial speed over adult T. Well, we can also write the volume as the surface area times the height so that comes density times, surface area times the height of the water times the initial velocity all over Delta team. And now, at this point, we could start calculating this. So we get the average force here. Um, this is given as the density, which is warden times tended our three kilograms per cubic meter. Our area is one square meter our height. How are we gonna do heights? So the height is given by five centimeters per hour. You okay? So what we're gonna do here is five times 10 to the negative two meters. This is divided by per one hour, and we're gonna compare this hour two seconds to do that, we've multiplied by 333,600 seconds per one hour, so these will cancel out. And the last thing we need is the initial velocity. That was eight minutes per second. So this delta T here was given by our rate of the rain accumulating right, because we have we were meaning a height over Delta T. And what we got right here is how much height of your late It's been an hour. So what we did is we have the height over the time it takes an hour, and that is our H over delta T. Okay, just wanna explain that a little bit more, and now we can plug stuff in. So if we plug all this in our calculator, we just get the average for South. It's all unless I units, we know where it is gonna be business. And we get out on average force of 0.11 suits cool.

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