Question
(II) The activity of a sample of 35 $\mathrm{S}\left(T_{\frac{1}{2}}=7.55 \times 10^{6} \mathrm{s}\right)$ is $2.65 \times 10^{5}$ decays per second. What is the mass of the sample?
Step 1
The formula is: \[ A = \lambda N \] where \( A \) is the activity, \( \lambda \) is the decay constant, and \( N \) is the number of radioactive nuclei. Show more…
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