00:01
Here the direction of omega sub 1 is along the axle of the wheel, and this is to the left.
00:24
So we can then say that this is the negative i hat direction.
00:33
We can also say that the direction for omega sub 2, this is along the axis of rotation, and which is straight up.
00:51
So this is straight upwards.
00:58
And so the direction for omega sub 2, this would be the positive k hat direction.
01:06
These would be your answers for part a.
01:09
For part b, they want us to find the magnitude of the angular velocity.
01:15
This would be the square root of omega sub 1 squared plus omega sub 2 squared.
01:20
This is simply due to pythagorean's theorem.
01:22
And this would be the square root of 44 .0 radians per second quantity squared plus 35 .0 radians per second quantity squared.
01:38
And we find that omega, the magnitude of the angular velocity would be 56 .2 radians per second.
01:49
And if we wanted to find the angle between the two, rather the angle with the angle between the two angular velocities or the angle with which the magnitude of the angular velocity is directed, we can say theta would be equaling arc tan of omega sub 2 divided by omega sub 1.
02:14
And so this would be arc tan of 35 .0 divided by 44 .0.
02:24
And this is equaling 38 .5 degrees...