(II) The cable supporting a 2125-kg elevator has a maximum strength of 21,750 N. What maximum upward acceleration can it give the elevator without breaking?

Answer

0.44$m / s^{2}$

October 23, 2020

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Christina K.

Rutgers, The State University of New Jersey

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Video Transcript

let's talk about this question. Uh Is that a cable supporting our 2125 kg alligator has a maximum strength or 21 7 15. Newtons, sort of the maximum upward acceleration that can give to the elevator without breaking. So if we draw of trying to draw a trigger, this is how the elevator looks like. Here, we have attention and this is the weight of the elevator and this is going up with acceleration of you. Now uh if you write the equation of motion, that's going to be a question of the forest, that's gonna be t minus W. Is equal to uh is equal to M. A. Uh So uh from here the value of acceleration comes out of steam minus W. O. R. M. Now we need to, the way it is definitely fixed. That's 2125 times 9.8. So that's fixed and the masses already 1-5. Now in order to find the maximum acceleration, we need to insert the maximum value of the tension. So that's going to be looking looking like this. 2125 2125 times 9.8 or 2125. So maximum value of the tension has now given us 21750. So we're gonna plug that in uh oh 21750 minus 2125 times 9.8 over 2125. This is something which we have to find. Let me grab my calculator here. So we have our 2125 times 9.8 and 21 75 0 minus this over 2125. That's going to be 0.44 up to two decimal places. That's going to be zero point for for meet up a second. That is the maximum acceleration, which the Liberator can have. Thank you.

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