00:01
29 .10, the equilibrium separation of the hydrogens in molecular hydrogen is 0 .074 nanometers.
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So we want to use this information to calculate the energy and wavelengths of the photons that we get out of these rotational transitions of the molecule.
00:27
So what we need is this h squared over 2i, h -bar squared, sorry.
00:40
And since we already know what h -bar is, let's figure out what the moment of inertia is.
00:47
So, you know, our molecule sort of looks something like this.
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This distance is r, and this is the center of mass.
01:01
And since we're considering it, you know, rotating about it center of mass, then, well, first of all, we're going to to have two because we have two point we have a point rotating about some axis and another point rotating about the same axis and they just add and then of course the mass of a hydrogen atom and then the distance squared for one of them because we're counting them both with the two here and so then this just simplifies to one half mh r squared and so then this characteristic rotational energy h bar squared over two i just h bar squared over two times this is mhr squared and so this is 7 .607 times 10 to the negative third electron volts and so further we have that the change in energy between you know some l initial to l final is the initial l times this h far squared over 2 i we just found the value of and then for a photon, its wavelength is hc over delta e.
03:22
And so now using our value for h -bar squared over 2i, we can find, just plug that in to this for each of our l values and also find the wavelength.
03:40
So here our l initial is 1.
03:48
And so just putting that in here, we get the energy...