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(II) The net force exerted on a particle acts in the positive $x$ direction. Its magnitude increases linearly from zero at $x = 0 ,$ to 380$\mathrm { N }$ at $x = 3.0 \mathrm { m }$ . It remains constant at 380$\mathrm { N }$ from $x = 3.0 \mathrm { m }$ to $x = 7.0 \mathrm { m } ,$ and then decreases linearly to zero at $x = 12.0 \mathrm { m } .$ Determine the work done to move the particle from $x = 0$ to $x = 12.0 \mathrm { m }$ graphically, by determining the area under the $F _ { x }$ versus $x$ graph.

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$3.0 \times 10^{3} \mathrm{J}$

Physics 101 Mechanics

Chapter 7

Work and Energy

Work

Kinetic Energy

Potential Energy

Energy Conservation

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Lectures

04:05

In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

03:47

In physics, the kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. The kinetic energy of a rotating object is the sum of the kinetic energies of the object's parts.

03:05

(II) The net force exerted…

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The net force exerted on a…

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'The force acting on …

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As a particle moves along …

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A force $F(x)=(3.0 / x) \m…

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The force on a particle is…

07:33

The force acting on a part…

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(II) The force on a partic…

04:53

7.37. So we're given a verbal description of the Net force that's exerted on a particle. We're told that it acts in the positive X direction. Uh, and let's just start sketching it now because we want to graphically find the work. It's done, so it starts it. We'll have force in Newton's and exit meters, so it starts at zero and then increases linearly 2 380 Newton's and three meters. No. Then it stays constant. Okay, over to seven meters and then it decreases linearly again to zero at X equals 12 meters. And so the work that's done by the forest going from 0 to 12 meters is the area under you. This force curve because this is a trap is oId weaken. Just directly compute the area, using our knowledge of geometry. And we don't have to do any calculus toe find the integral. So the work 1/2 12 meters plus four meters times 380 Newton's. So this is 3.0 killer. Jules is the total work that is done by this force moving the particle from 0 to 12 meters

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